General Navigation

A study guide for the EASA ATPL General Navigation subject: the Earth and time, direction and magnetism, compasses, units, speed and altitude, chart projections, dead reckoning and wind, in-flight navigation, the point of equal time and the point of safe return, and inertial navigation with the FMS.

  1. 01 · The Solar System
  2. 02 · The Earth: Position & Distance
  3. 03 · Time & Time Conversion
  4. 04 · Direction & Terrestrial Magnetism
  5. 05 · Compasses
  6. 06 · Units, Speed & Altitude
  7. 07 · Chart Principles & Scale
  8. 08 · Mercator Projections
  9. 09 · Lambert Conformal Conic
  10. 10 · Polar Stereographic & Grid
  11. 11 · Dead Reckoning & Wind
  12. 12 · In-Flight Navigation
  13. 13 · PET & Point of Safe Return
  14. 14 · Inertial Navigation & FMS
  15. 15 · Related Subjects

01 The Solar System

Everything in navigation that involves time, daylight and the Sun goes back to two facts: the Earth spins on a tilted axis, and it moves round the Sun on a slightly elliptical orbit.

Kepler and the orbit

Axial tilt and seasons

The Earth's axis is inclined 66½° to the plane of its orbit, which is the same as saying the equator is inclined 23½° to the ecliptic (the Sun's apparent yearly path). This obliquity is constant through the year, and it causes the seasons and the changing length of day and night.

Sun 21 JunN summer solstice 21 DecN winter solstice 23 Sep · equinox 21 Mar · equinox
The axis keeps the same direction in space all year. In June the northern hemisphere leans towards the Sun; in December it leans away.

Declination and the special parallels

The Sun's declination is its angular distance north or south of the celestial equator. It swings between 23½°N (June solstice) and 23½°S (December solstice), passing 0° at the equinoxes, when it changes fastest.

ParallelLatitudeMeaning
Tropics of Cancer / Capricorn23½° N / SHighest latitude where the Sun can be vertically overhead
Arctic / Antarctic Circle66½° N / SLowest latitude with at least one day of midnight sun (and one of polar night)
Midnight sun rule: with declination d, the Sun stays up all day poleward of latitude (90° − d) on the same side, and stays below the horizon poleward of (90° − d) on the other side. Declination 12°S → midnight sun south of 78°S.

Daylight

Years

Tropical year (seasons, calendar)365 d 5 h 48 min 45 s
Sidereal year (relative to the stars)≈ 365 d 6 h 9 min
Exam traps. "Seasons are caused by the elliptical orbit" is always wrong. The angle between the equator and the ecliptic is 23½°; the angle between the axis and the orbital plane is 66½° — read which one is asked. "Sidereal" refers to the stars.

02 The Earth: Position & Distance

This is the largest chapter of the exam. Master five tools — d.lat, d.long, departure, convergency and conversion angle — and most "position" questions become two-line calculations.

Shape of the Earth

Circles and lines

LineDefinitionNotes
Great circlePlane passes through the Earth's centreShortest distance (shorter arc); the equator and every meridian pair are GCs; radio waves travel along GCs
Small circlePlane does not pass through the centreAll parallels except the equator
Rhumb line (loxodrome)Cuts every meridian at the same angleConstant true track; spirals towards the poles; parallels and meridians are special rhumb lines

A parallel of latitude (other than the equator) is a small circle and a rhumb line, but not a great circle. A meridian is half a great circle, running true north–south from pole to pole. Longitude runs 0–180° E or W; the 180° meridian is the Greenwich anti-meridian.

Distance

1′ of great-circle arc = 1 NM  ·  1° = 60 NM  ·  Earth's circumference = 21 600 NM
Departure (NM) = d.long (′) × cos lat   |   Length of a parallel = 21 600 × cos lat

Departure is the east–west distance along a parallel. It is greatest at the equator and zero at the poles. For two different latitudes use the mean latitude.

An aircraft at 60°N 005°W tracks 090°T for 315 km. Final longitude?
315 km ÷ 1.852 = 170 NM. d.long = 170 / cos 60° = 340′ = 5°40′. 005°W + 5°40′ east → 000°40′E.
From 04°00′N 030°00′W fly 600 NM S, 600 NM E, 600 NM N, 600 NM W. Final position?
The eastward leg is flown at 6°S (cos 6° → 603.3′ d.long), the westward leg at 4°N (cos 4° → 601.5′). Net 1.8′ east → 04°00′N 029°58′W. Whenever the "box" legs are flown at different latitudes, the leg nearer the equator covers less longitude per NM.

Great circle versus rhumb line

NORTH POLE ↑ AB Great circle — initial 081°, final 099° Rhumb line — constant 090° CA
Northern hemisphere, eastbound along a parallel. The GC always lies on the polar side of the rhumb line; the RL lies nearer the equator.

Convergency and conversion angle

Convergency = d.long × sin (mean lat)   |   Conversion angle (CA) = ½ × convergency
Sign rule: the GC is always nearer the pole. Northern hemisphere: eastbound GC tracks increase (081° → 099°), westbound they decrease (279° → 261°). Southern hemisphere: the opposite. In both hemispheres the GC and RL directions are equal at the mid-longitude.
A (55°N 000°) to B (54°N 010°E). GC track at A = 100°T. RL track at A?
Convergency = 10 × sin 54.5° ≈ 8.1°, CA ≈ 4°. NH eastbound: GC starts left (north) of the RL, so RL = 100 + 4 = 104°.
INS flies the GC from 60°N 030°W to 60°N 020°W. Latitude at 025°W?
The vertex is at mid-longitude. tan(latV) = tan 60° / cos 5° → 60°05.7′N. On the next GC leg (020°W → 010°W) the track changes by the full convergency (≈ 9°) at the waypoint.

Vertex, antipodes and paths over the pole

Exam traps. km and statute miles do not change with latitude — only d.long converts with cos lat. "Shortest distance" is the arc of a great circle. The RL track A→B and B→A are exact reciprocals; GC tracks are not. A constant true track is always a rhumb line.

03 Time & Time Conversion

Time questions are pure arithmetic once you have the arc-to-time table in your head and always pass through UTC.

Kinds of time

TermMeaning
Apparent (solar) timeBased on transits of the real Sun. Apparent days vary in length (elliptical orbit + obliquity).
Mean timeBased on an imaginary mean sun moving at constant speed along the celestial equator. Every mean day is 24 h.
Equation of timeApparent − mean. Largest in February (≈ −14 min) and November (≈ +16 min).
LMTMean time on the local meridian. 1200 LMT = mean sun over the meridian (upper transit); 0000 LMT = mean sun over the anti-meridian (lower transit).
UTCCo-ordinated Universal Time ≈ LMT at Greenwich; the aviation reference.
Standard timeThe time set by law for a country or region; may differ from UTC by non-whole hours. Summer time (DST) usually adds 1 h.

Arc and time

360° = 24 h  ·  15° = 1 h  ·  1° = 4 min  ·  15′ = 1 min  ·  1′ = 4 s
Longitude east, Greenwich least; longitude west, Greenwich best.
LMT = UTC + E long (in time)    LMT = UTC − W long (in time)
LMT at 65°25′N 123°45′W at 2200 UTC?
123°45′ = 8 h 15 min. West → subtract: 2200 − 0815 = 1345 LMT. Latitude plays no part.
Depart Guam (UTC+10) 2300 ST 30 April, flight time 11 h 15. Arrival time in Los Angeles (UTC−7 in summer)?
2300 − 10 = 1300 UTC 30 Apr. + 11:15 = 0015 UTC 1 May. − 7 h = 1715 on 30 April. Always convert to UTC first, add flight time, then convert to the destination's time.

The International Date Line

The date line follows the 180° meridian, bending round island groups. Crossing it westbound (from the east, e.g. USA → Japan) the date increases by one; crossing eastbound it decreases. Standard-time questions handle this automatically if you work through UTC.

Sunrise, sunset and twilight

TwilightSun's centre below the horizon
Civil0° → 6°
Nautical6° → 12°
Astronomical12° → 18°

Twilight lasts longer at high latitudes, where the Sun crosses the horizon at a shallow angle. ICAO night: from the end of evening civil twilight to the beginning of morning civil twilight (or as prescribed by the authority).

Sunrise at 52°S 040°E is 0243 UTC. Same day, sunrise at 52°S 035°W?
Same latitude → same LMT of sunrise. The second place is 75° further west = 5 h later in UTC: 0743 UTC.
Exam traps. The question may give standard time at one place and ask for LMT at another — two different conversions. "Slow on UTC" means behind UTC, i.e. western longitudes. Civil twilight begins/ends at 6°, nautical at 12°, astronomical at 18°.

04 Direction & Terrestrial Magnetism

Directions are only meaningful with a reference: true, magnetic, compass or grid. The heading chain from compass to true is the most-tested routine in the exam.

The Earth's magnetic field

H = T cos (dip)  ·  Z = T sin (dip)  ·  tan (dip) = Z / H
Magnetic equatorMagnetic poles
Dip0° (aclinic line)90°
HMaximum — compass works best≈ 0 — compass useless
Z0 — no acceleration/turning errorsMaximum
TWeakestStrongest

Variation

Variation is the angle between true north and magnetic north, named east (+) or west (−). It can reach 180° (between the geographic and magnetic poles) and it changes slowly over time because the magnetic poles wander — the annual change can increase or decrease the value depending on where you are.

IsogonalLine of equal variation
Agonic lineZero variation (true and magnetic meridians coincide)
IsoclinalLine of equal dip
Aclinic lineZero dip = magnetic equator

Isogonals converge at the magnetic poles (and the geographic poles, where all meridians meet).

Deviation

Deviation is the angle between magnetic north and compass north, caused by the aircraft's own magnetism. It changes with heading and is recorded on the compass deviation card.

The heading chain

TRUE MAGNETIC COMPASS variation deviation W: add · E: subtract W: add · E: subtract
True → Magnetic → Compass: "West is best, east is least". Going the other way (C → M → T), add east and subtract west.
Track to compass heading in four steps: (1) apply drift — drift right means steer left of track, so HDG(T) = TR − drift R / + drift L; (2) variation west add, east subtract; (3) deviation west (−) add, east (+) subtract; (4) read the compass heading.
True track 348°, drift 17° left, variation 32°W, deviation 4°E. Compass heading?
Drift left → steer right: 348 + 17 = 005°T. +32 (W) = 037°M. −4 (E) = 033°C.
True track 180°, drift 8° R, compass heading 195°, deviation −2°. Variation?
HDG(T) = 180 − 8 = 172°. HDG(M) = 195 − 2 = 193°. Magnetic exceeds true by 21° → 21°W.

Radio bearings and variation

Exam traps. "Deviation +4" means easterly, so compass heading is 4° less than magnetic. A westerly variation means true north lies east of magnetic north. The magnetic equator is the aclinic line, not the agonic line.

05 Compasses

The direct reading compass is simple and independent of electrics, but its errors in turns and accelerations are a favourite exam topic. The remote indicating compass fixes most of them.

Direct reading compass (DRC) — requirements

RequirementHow it is achieved
Horizontality (counter dip)Pendulous suspension: pivot above a low centre of gravity, so the magnet hangs nearly level
SensitivityStrong magnets with small mass; jewelled pivot; liquid reduces pivot friction. Sensitivity ∝ H
Aperiodicity (dead-beat)Mass concentrated near the pivot (small moment of inertia), damping wires and damping liquid

Acceleration errors

The magnet's CG sits on the equator side of the pivot (offset by dip). Speed changes on east/west headings swing it, giving a false turn. No error on north/south headings, and none at the magnetic equator.

ANDS (northern hemisphere): Accelerate → apparent turn North; Decelerate → apparent turn South. In the southern hemisphere the error is reversed: accelerate → apparent turn south. (Easy form: acceleration always shows a turn towards the nearer magnetic pole.)
NH caseIndicationCard / magnet (seen from above)
Accelerate on 090°Turn to north (reading decreases)Clockwise
Accelerate on 270°Turn to north (reading increases)Anticlockwise
Decelerate on 270°Turn to southClockwise

Turning errors

Turning errors are greatest when turning through north and south, and grow with magnetic latitude; nil through east and west.

UNOS (northern hemisphere): through the nearer pole (north) the compass is sluggish and under-reads → Undershoot North (roll out before the compass shows the heading). Through the further pole (south) the compass is lively and over-reads → Overshoot South (roll out after). Liquid swirl adds to the error in both cases.
NH, rate-one turn right from 135° for 30 s (90°). What does the compass show at roll-out?
The turn passes through south, where the compass leads: it reads more than 225°. From 330° to 060° (through north) it would read less than 060°.

Aircraft magnetism and deviation

Coefficients and the compass swing

Dev = MH − CH  ·  A = mean of all deviations  ·  B = (dev E − dev W)/2  ·  C = (dev N − dev S)/2
MH/CH: 358/356, 091/087, 182/186, 273/271. Coefficient A and B?
Deviations: +2, +4, −4, +2. A = (+2+4−4+2)/4 = +1. B = (+4 − (+2))/2 = +1.

Remote indicating (gyro-magnetic) compass

Exam traps. Compass sensitivity is proportional to H, not Z. ANDS reverses in the southern hemisphere. Coefficient C uses north and south headings; B uses east and west.

06 Units, Speed & Altitude

Conversion questions are free marks if the factors are memorised and the flight computer is used carefully. Keep the units straight before you calculate.

Distance and length

1 NM1 852 m · 6 076 ft · 1.15 SMAverage length of 1′ of arc of a meridian
1 SM1 609 m · 5 280 ft
1 km3 280 ft · 0.54 NMOriginally 1/10 000 of the equator–pole meridian distance
1 m3.281 ft
1 inch2.54 cm

ICAO units: horizontal distance in m, km and NM; heights and altitudes in ft or m; speed in kt (or km/h); vertical speed in ft/min or m/s.

Speed, time, distance

Time = Distance / GS  ·  GD = AD × GS / TAS  ·  1 m/s ≈ 1.944 kt  ·  100 ft/min ≈ 0.51 m/s
GS 122 kt, distance 985 NM. Time?
985/122 = 8.074 h → 0.074 × 60 = 4.4 min → 8 h 04 min. Convert decimal hours carefully: 0.1 h = 6 min.

Volume and mass of fuel

1 US gal3.785 L
1 imp gal4.546 L = 1.2 US gal
1 kg2.205 lb
MassVolume (L) × specific gravity = kg
Fuel flow 22 US gal/h, fuel on board 83 imp gal. Endurance?
83 × 1.201 = 99.7 US gal ÷ 22 = 4.53 h ≈ 4 h 32 min. Put both quantities in the same gallon first.

Airspeeds and Mach

LSS (kt) = 38.94 √T(K)  ·  M = TAS / LSS  ·  LSS ≈ 644 + 1.2 × t(°C)
TAS 487 kt at FL330, ISA +15. Mach number?
ISA at FL330 = 15 − 2 × 33 = −51 °C; +15 → −36 °C = 237 K. LSS = 38.94 × √237 ≈ 600 kt. M = 487/600 ≈ 0.81.

Ram rise: a total-air-temperature probe reads warm. Rise ≈ (TAS/100)² °C, so COAT ≈ IOAT − (TAS/100)².

Altimetry for navigation

ISA: 15 °C at MSL, −1.98 °C per 1 000 ft · 1 hPa ≈ 27–30 ft near MSL
PA 29 000 ft, OAT −55 °C. Density altitude?
ISA at 29 000 ft = −43 °C → ISA −12. DA ≈ 29 000 − 12 × 120 ≈ 27 500 ft.
Exam traps. A distance in km or SM never changes with latitude. Time-to-go uses GS, never TAS. Check whether the question gives US or imperial gallons, and litres or kg.

07 Chart Principles & Scale

No flat chart can show a sphere without distortion. The chart-maker chooses which property to keep; for aviation that is almost always correct angles (conformality).

Desirable properties

Projection surfaces

SurfaceProjectionTypical use
CylinderMercator (direct, transverse, oblique)Equatorial, N–S strips, GC routes
ConeLambert conformal conicMid-latitude en-route charts
PlanePolar stereographic (azimuthal)Polar navigation

Charts with straight meridians and scale varying with latitude, and curved rhumb lines: Lambert and polar stereographic.

Scale

Scale = chart length / earth length  ·  1 NM = 185 200 cm  ·  1 km = 100 000 cm

A larger scale (1:250 000) shows more detail than a smaller one (1:1 000 000).

A line 4.63 cm long represents 150 NM. Scale?
150 × 185 200 = 27 780 000 cm. 27 780 000 / 4.63 ≈ 6 000 000 → 1 : 6 000 000.
Chart 1:500 000. What does 7 cm represent?
7 × 500 000 = 3 500 000 cm = 35 km (≈ 19 NM).

Chart features

Exam traps. Use 185 200 cm per NM, not 185 000. When the question says "earth distance", convert cm to km first, then to NM if needed.

08 Mercator Projections

On a direct Mercator chart, a straight line is a rhumb line. That one property explains the chart's strengths (constant-track plotting) and its weaknesses (scale expansion, no poles).

Direct Mercator

0°20°40°60°75° rhumb line (straight) great circle
Meridians: parallel, equally spaced, vertical. Parallels: straight, parallel, spacing increasing with latitude. Great circles are curves convex to the nearer pole (concave to the equator).
Scale at lat = Scale at equator × sec lat  ·  chart length of d.long is the same at every latitude
Scale 1:3 704 000 at the equator. Scale at 60°S?
Denominator × cos 60° = 1 852 000 → 1 : 1 852 000 (a larger scale).
At 45°N a chart length represents 90 NM. What does it represent at 30°N?
Earth distance ∝ cos lat: 90 × cos 30°/cos 45° ≈ 110 NM.
The 53°N parallel measures 133 cm. Scale at 30°S?
Every parallel = equator length on the chart: 133 cm ↔ 21 600 NM → 1 : 30 000 000 at the equator; × cos 30° ≈ 1 : 26 000 000.

Transverse Mercator

Oblique Mercator

Exam traps. On Mercator the GC lies on the polar side of the straight rhumb line. "Scale expands as the secant of latitude" — not cosine. Transverse = N–S countries; oblique = GC routes.

09 Lambert Conformal Conic

The Lambert conformal conic is the standard en-route chart for mid-latitudes. A straight line is very nearly a great circle, and the chart's convergence is fixed by one number: the constant of the cone, n.

Construction

standard parallel parallel of origin standard parallel scale: correct on standard parallels, contracted between, expanded outside

The constant of the cone

n = sin (parallel of origin) ≈ sin (mean of the standard parallels)  ·  Chart convergence = d.long × n
Standard parallels 63°N and 41°N. Constant of the cone?
Mean = 52°; n = sin 52° ≈ 0.788.
n = 0.75. A straight line from 45°N 060°W is 055°T at A. Direction at B on 028°W?
Chart convergence = 32° × 0.75 = 24°. Track at B = 055 + 24 = 079°T. The rhumb line A→B ≈ 055 + 12 = 067°T.
Plotting an NDB bearing on a Lambert chart (parallel of origin 51°N). Aircraft 66°N 029°W, NDB 64°N 022°W, QDR at aircraft 118°T.
Reciprocal at the aircraft = 298°T. Chart convergence = 7 × sin 51° ≈ 5.4°. Measured at the NDB the line plots as 298 + 5.4 ≈ 303.4°T.

Measuring distance

Measure distance with the latitude scale near the middle of the line, or use the quoted scale between the standard parallels.

Course 120°T from 61°30′N to 58°30′N, scale 1:1 000 000 at 60°N. Chart distance?
d.lat 3° = 180 NM; at 120°, distance = 180 / cos 60° = 360 NM = 666.7 km → 66.7 cm.
Exam traps. n uses sine, never cosine. "Scale constant along a parallel" is true; "constant over the chart" is false. Earth convergency correct at the parallel of origin, scale correct at the standard parallels.

10 Polar Stereographic & Grid

Near the poles meridians converge so quickly that true direction becomes useless for steering. The polar stereographic chart and a grid overlay give a direction that stays constant along a straight line.

Polar stereographic projection

Straight line from 70°N 060°W to 70°N 060°E. Initial true track?
d.long 120° and n = 1, so the line leaves half of 120° from the rhumb line (090°): 090 − 60 = 030°T. Its highest latitude is reached at the mid-longitude, 000°.

Grid navigation

Gridding a chart = choosing a datum meridian and drawing lines parallel to it. Grid north is the direction of the datum meridian towards the North Pole. A straight line then keeps a constant grid track even though its true track changes.

000° (datum)090°W090°E180° grid lines ∥ datum meridian Northern hemisphere: G = T + W long − E long Southern hemisphere: G = T − W long + E long (longitude from the datum)
Grid convergence (NH, Greenwich datum) = longitude: G = T + long W · G = T − long E

For a datum other than Greenwich, use the longitude difference from the datum. In the southern hemisphere the signs reverse.

Grivation

Grivation = grid convergence + variation (algebraically)  ·  G = M + grivation (W add, E subtract — like variation)
75°N 140°W, true heading 330°. Grid aligned with Greenwich. Grid heading?
NH: G = T + W long = 330 + 140 = 470 → 110°G.
Thule (76°32′N 068°15′W, variation 75°W). Track radial 210 inbound. Grid track (Greenwich grid)?
Inbound on radial 210 = 030°M. True = 030 − 75 = 315°T. Grid = 315 + 68 = 383 → 023°G.
South polar chart, grid on Greenwich. Route 85°S 100°E → 85°S 140°W. Grid track, and true track at 180°?
Mid-longitude 160°E: true track 090°. SH: G = T + E long = 090 + 160 = 250°G (constant). At 180°: T = 250 − 180 = 070°T.
Exam traps. Check the hemisphere before applying the grid formula. Grid track is constant along a straight line on the chart; true track is not. Grivation includes variation, convergence does not.

11 Dead Reckoning & Wind

Dead reckoning is the triangle of velocities: what the aircraft does through the air, what the air does over the ground, and the result over the ground. Every wind question is one of three unknown sides.

The triangle of velocities

HDG / TAS (one arrow) W/V (three) TR / GS (two arrows) drift
Drift is the angle from heading to track. Wind from the left → drift right; wind from the right → drift left.
Wind direction is where it blows FROM. ATIS/tower winds are magnetic (match the runway QDM); forecast/upper winds are true.

Quick trigonometry (or the CRP-5)

WCA ≈ W × sin(wind angle) / TAS  (in radians → × 57.3, or use 60/TAS × crosswind)
GS ≈ TAS × cos(WCA) − W × cos(wind angle)
Headwind = W × cos θ  ·  Crosswind = W × sin θ  (θ = angle between wind and runway/track)
θ10°20°30°45°60°90°
sin θ0.170.340.50.710.871

Maximum drift occurs with the wind at 90° to the heading (not the track); maximum drift angle = sin⁻¹(W/TAS).

TAS 140 kt, HDG 005°T, W/V 265/25. Drift and GS?
Wind is from the left-rear → drift right. Crosswind ≈ 25 × sin 100° ≈ 24.6 kt → drift ≈ 24.6/140 × 57 ≈ 10° R. Tailwind component ≈ 4 kt → GS ≈ 146 kt, 10° R.
Tailwind limit 10 kt. RWY 05 (QDM 047°), ATIS wind 210°, variation 17°E. Maximum wind strength?
ATIS wind is magnetic: 210 − 047 = 163° off the nose, i.e. 17° from a direct tailwind. W = 10 / cos 17° ≈ 11 kt. (Applying variation here is the trap.)
HDG 090°C, dev 2°W, var 12°E, TAS 160. Holding the 070 radial outbound, 14 NM in 6 min. W/V?
HDG(T) = 090 − 2 + 12 = 100°. Track = 070 + 12 = 082°T, GS = 140 kt. Solving the triangle: 160°/50 kt.

Air plot and ground plot

Exam traps. Do not apply variation to an ATIS wind against a magnetic runway. Drift and wind correction angle are equal and opposite. "Track" questions want TR/GS from HDG/TAS; "heading" questions want HDG/GS from TR/TAS.

12 In-Flight Navigation

In-flight navigation is about correcting the plan with what the aircraft actually does: track errors, revised ETAs, speed changes to meet a time, and descent planning. The 1-in-60 rule does most of the work.

The 1-in-60 rule

Angle (°) ≈ 60 × offset / distance  ·  1° at 60 NM ≈ 1 NM
AB off-track TECA distance gonedistance to go
To regain track and reach B: Track error TE = 60 × off / distance gone. Closing angle CA = 60 × off / distance to go. Alter heading by TE + CA, towards the track. To fly parallel to the planned track, alter by TE only.
A to B 100 NM. Fix 40 NM along, 6 NM left of track. Alteration to reach B?
TE = 6/40 × 60 = 9°. CA = 6/60 × 60 = 6°. Alter 15° right.

A heading error from using the wrong variation sign (2°E instead of 2°W = 4°) gives an off-track distance of 4/60 × distance (200 NM → ≈ 13–14 NM).

Revised ETA and required groundspeed

A→B 480 NM, planned GS 240 kt, depart 1000. After 150 NM the aircraft is 2 min late. Revised ETA?
Planned 150 NM = 37.5 min; actual 39.5 min → GS = 150/39.5 × 60 ≈ 228 kt. 330 NM to go ÷ 228 ≈ 87 min. ETA = 1000 + 39.5 + 87 ≈ 1206.
475 NM, planned GS 315, ATD 1000. At 1040 the fix is 190 NM along. GS needed for the planned ETA?
Planned ETA = 1000 + 90.5 min = 1130.5. 285 NM in 50.5 min → ≈ 340 kt.

Losing time: speed reductions

Work in groundspeed, convert to TAS (GS − wind component), then to IAS or Mach.

FL120, IAS 200 kt, −5 °C, tailwind 30 kt. Lose 5 min over the last 100 NM. New IAS?
TAS ≈ 240 kt → GS 270 kt → 22.2 min. Need 27.2 min → GS 220.4 → TAS 190.4. Ratio IAS/TAS ≈ 0.83 → new IAS ≈ 159 kt (a reduction of ≈ 41 kt).

Climb and descent

ROD (ft/min) = height to lose / time  ·  time = distance / GS
ROD ≈ GS (NM/min) × 6 076 × gradient  ≈  gradient(%) × GS(kt)
3° glide path ≈ 300 ft per NM  ·  ROD on 3° ≈ 5 × GS
FL370 to cross a DME at FL120, start 100 NM out, mean GS 396 kt. Minimum ROD?
25 000 ft in 100/396 h = 15.15 min → ≈ 1 650 ft/min.
3° ILS, threshold crossing height 50 ft, 25 NM DME. Height above threshold?
25 × 300 = 7 500 + 50 = 7 550 ft. Glide path capture at 2 500 ft → 2 500/300 ≈ 8.3 NM.

Position lines from radar, NDB and VOR

Island 30° left on the radar, MH 276°, variation 12°W. True bearing of the aircraft from the island?
HDG(T) = 264°. Island bears 264 − 30 = 234°T. From the island: 054°T.
At 0020 on the 310° radial at 40 NM; at 0035 on the 040° radial at 40 NM (variation 0). Track and GS?
The radials are 90° apart, so the chord = 2 × 40 × sin 45° ≈ 56.6 NM. The track is perpendicular to the bisecting radial (355°), moving clockwise: 085°T. GS = 56.6 NM in 15 min ≈ 226 kt.

Visual navigation

Exam traps. Use distance gone for TE and distance to go for CA. Speed-change questions are in GS until the end. A 6 % gradient is not 6°: 6 % ≈ 3.4°.

13 PET & Point of Safe Return

Two points answer two different questions. The PET (point of equal time, or critical point) tells you where going on and turning back take the same time. The PSR/PNR (point of safe return) tells you how far you can go and still get back with the fuel you have.

Point of Equal Time (PET / CP)

Distance to PET:   x = D × H / (O + H)   ·   Time to PET = x / O

D = total distance, O = groundspeed onward (continuing), H = groundspeed home (returning). Both GS are those that apply after the decision — e.g. with one engine out, use the reduced TAS for O and H, but use the normal GS to work out the time taken to reach the PET.

D = 1 973 NM, O = 430 kt, H = 385 kt. Time to PET?
x = 1 973 × 385 / 815 ≈ 932 NM. Time = 932 / 430 ≈ 130 min.
D = 450 NM, WC out +30, back −40, TAS 160 kt, reduced TAS 130 kt. Time from C to the PET (based on reduced TAS)?
After failure O = 130 + 30 = 160, H = 130 − 40 = 90. x = 450 × 90/250 = 162 NM. Flown at normal GS (190 kt): 51 min.

Point of Safe Return (PSR / PNR)

Time to PSR:   T = E × H / (O + H)   ·   Distance to PSR = T × O = E × O × H / (O + H)

E = safe endurance (usable fuel excluding reserves, expressed as time). The PSR depends on fuel and groundspeeds, not on the distance to destination.

D = 2 346 NM, O = 365 kt, H = 480 kt, E = 8 h 30. Time to PSR?
T = 510 × 480 / 845 ≈ 290 min (distance ≈ 1 762 NM).
TAS 180 kt, track 090°, W/V 045/50. How far out and back in one hour?
GS out ≈ 141 kt, home ≈ 212 kt. Radius = 1 × 141 × 212 / 353 ≈ 85 NM.

Multi-leg and fuel-based PNR

When wind or fuel flow changes along the route, work leg by leg: subtract the fuel used out-and-back on each whole leg from the usable fuel, then find how far into the next leg the remaining fuel takes you out and back (fuel per NM out + fuel per NM home).

Exam traps. PET uses the post-failure groundspeeds; the time to the PET uses the speed you are actually flying. "Distance from PET to B" = D − x. A PSR beyond the destination is a legitimate answer.

14 Inertial Navigation & FMS

Inertial systems navigate with no external signals at all: they measure acceleration, integrate it into velocity and then into distance. In the current ATPL structure this material sits mainly under Radio Navigation, but it appears throughout these General Navigation banks.

Principle

acceleration velocity (GS) distance ∫ 1st ∫ 2nd N/S channel → change of latitude · E/W channel → departure → change of longitude

INS versus IRS

INS (gimballed)IRS (strap-down, ring laser gyros)
SensorsOn a gyro-stabilised platformFixed to the airframe; platform computed
Alignment at mid-latitudes≈ 15–20 min≈ 10 min
Special errorsGyro driftLock-in at low rotation rates, cured by dither (piezo-electric motor)

Alignment and modes

Errors

FMS (B737 type)

Exam traps. First integration = velocity, second = distance. The IRS is not updated in flight. Gyrocompassing is ground-only. Dither cures lock-in.

15 Related Subjects

These questions appeared in the General Navigation sources but belong to other ATPL subjects (031 Mass & Balance, 033 Flight Planning, 062 Radio Navigation, 022 Instruments). They are kept here for completeness.

Mass and traffic load

ZFM = DOM + traffic load · TOM = ZFM + take-off fuel · LM = TOM − trip fuel

The maximum traffic load is the smallest of: MZFM − DOM; MTOM − DOM − take-off fuel; MLM − DOM − landing fuel; MRM − DOM − ramp fuel.

A forward CG increases longitudinal stability and reduces manoeuvrability (more elevator force needed).

Radio aids